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$S{O_{3(g)}} \rightleftharpoons S{O_{2(g)}} + 1/2\,{O_{2(g)}}$ is $4.9 \times 10^{-2}$ then find equilibrium constant for the reaction
$2S{O_{2(g)}} + {O_{2(g)}} \rightleftharpoons 2SO_3(g)$
$\begin{array}{*{20}{l}}
{(u){H_2}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} CHC{H_3}{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (v){\mkern 1mu} C{H_2}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} CHCl{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (w){\mkern 1mu} C{H_3}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} H_2^ + {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (x){\mkern 1mu} H - C \equiv C - H} \\
{(y){\mkern 1mu} C{H_3}\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{C} N{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} (z){\mkern 1mu} {{(C{H_3})}_2}C\underset{\raise0.3em\hbox{$\smash{\scriptscriptstyle-}$}}{N} N{H_2}}
\end{array}$
$\begin{array}{*{20}{c}}
{{{(C{H_3})}_2}CH - C{H_2}CH = CH - CH - CHC{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{C_2}{H_5}}
\end{array}$