MCQ
The oxidation state of nitrogen in ${N_3}H$ is
- A$ + \frac{1}{3}$
- B$+3$
- C$ - 1$
- ✓$ - \frac{1}{3}$
$\mathop {{N_3}H}\limits^{ * \,\,\,\,\,\,\,\,} $
$3x + 1 = 0$, $3x = - 1$, $x = - \frac{1}{3}$.
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$\begin{array}{*{20}{c}}
{\,\,\,\,\,C{H_3}} \\
| \\
{C{H_3} - C - ONa} \\
| \\
{\,\,\,\,\,C{H_3}}
\end{array}\, + \,C{H_3}C{H_2}Cl\,\xrightarrow{{ - NaCl}}\,$ $\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - O - C{H_2} - C{H_3}} \\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
is called