MCQ
The oxide without nitrogen-nitrogen bond is :
- A$\mathrm{N}_{2} \mathrm{O}$
- B$\mathrm{N}_{2} \mathrm{O}_{4}$
- C$\mathrm{N}_{2} \mathrm{O}_{3}$
- ✓$\mathrm{N}_{2} \mathrm{O}_{5}$

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$3HCHO+A\xrightarrow[{{40}\,^{o}}C]{N{{a}_{2}}C{{O}_{3}}}\underset{(82\%)}{\mathop{(B)}}$
Product $(B)$ of the above reaction is
$C{l_2} + 2B{r^ - }\left( {aq} \right) \to 2C{l^ - }\left( {aq} \right) + B{r_2}$
$Br_2$ gas thus formed is dissolved into solution of $Na_2CO_3$ and then pure $Br_2$ is obtained by treatment of the solution with
$C{H_3}COOH + PC{l_5} \to A\mathop {\xrightarrow{{{C_6}{H_6}}}}\limits_{anh.\,AlC{l_3}} $ $B\mathop {\xrightarrow{{{C_2}{H_5}MgBr}}}\limits_{ether} C$