The period of simple pendulum is measured as $T$ in a stationary lift. If the lift moves upwards with an acceleration of $5\, g$, the period will be
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(d) $\frac{{T'}}{T} = \sqrt {\frac{g}{{g' + a}}} = \sqrt {\frac{g}{{g + 5g}}} = \sqrt {\frac{1}{6}} $
==> $T' = \frac{T}{{\sqrt 6 }}$
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$(a)$ Potential energy is always equal to its $K.E.$
$(b)$ Average potential and kinetic energy over any given time interval are always equal.
$(c)$ Sum of the kinetic and potential energy at any point of time is constant.
$(d)$ Average $K.E.$ in one time period is equal to average potential energy in one time period.
Choose the most appropriate option from the options given below: