MCQ
The periodic time of a body executing simple harmonic motion is $3$ sec. After how much interval from time $t=0$, its displacement will be half of its amplitude
  • A
    $\frac{1}{8} sec$
  • B
    $\frac{1}{6} sec$
  • $\frac{1}{4} sec$
  • D
    $\frac{1}{3} sec$

Answer

Correct option: C.
$\frac{1}{4} sec$
$ y=a \sin \frac{2 \pi}{T} t $
$\Rightarrow \frac{a}{2}=a \sin \frac{2 \pi t}{3} $
$\Rightarrow \frac{1}{2}=\sin \frac{2 \pi t}{3} $
$ \Rightarrow \sin \frac{2 \pi t}{3}=\sin \frac{\pi}{6}$
$ \Rightarrow \frac{2 \pi t}{3}=\frac{\pi}{6}$
$\Rightarrow t=\frac{1}{4} \mathrm{sec}$

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