The piston in the cylinder head of locomotive has a stroke of $6\,m$ (which is twice the amplitude). If the piston executing simple harmonic motion with an angular frequency of $200\, rad\, min^{-1}$, its maximum speed is .... $ms^{-1}$
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Amplitude $=\frac{6}{2}=3 \mathrm{m}$

$\mathrm{V}_{\max }=\mathrm{A} \omega=3 \times \frac{200}{60}=10 \mathrm{ms}^{-1}$

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