MCQ
The plot of $\log\,K$ Vs $\frac{1}{T}$ helps to calculate
- AThe energy of activation
- BThe rate constant of the reaction
- CThe order of reaction
- ✓The energy of activation as well as frequency factor
$\log k=\log A-\frac{E_a}{2.303} \cdot \frac{1}{T}$
Plot of $\log k\,vs\, \frac{1}{ T }$ is a straight line.
Slope $=-\frac{ E _{ a }}{2.303 R }$
Intercept $=\log A$
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$(A)$ ${X}$ is a reducing sugar and ${Y}$ is a non-reducing sugar
$(B)$ ${X}$ is a non-reducing sugar and ${Y}$ is a reducing sugar
$(C)$ The glucosidic linkages in ${X}$ and ${Y}$ are $\alpha$ and $\beta$, respectively
$(D)$ The glucosidic linkages in ${X}$ and ${Y}$ are $\beta$ and $\alpha$, respectively
