The position co-ordinates of a particle moving in a $3-D$ coordinates system is given by $x = a\,cos\,\omega t$ , $y = a\,sin\,\omega t$ and $z = a\omega t$ The speed of the particle is
A$\sqrt 2 \,a\omega$
B$a\omega $
C$\sqrt 3 \,a\omega$
D$2\,a\omega $
JEE MAIN 2019, Medium
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A$\sqrt 2 \,a\omega$
a $\mathrm{v}_{\mathrm{x}}=\frac{\mathrm{d} \mathrm{x}}{\mathrm{dt}}=-\mathrm{a} \omega \sin \omega \mathrm{t}$
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