- AVoltage is less but current is more
- BBoth voltage and current are more
- CVoltage is more but current is less
- DBoth voltage and current are less
Explanation:
The power cables have some resistance.
Power lost in the wires can be calculated as P = I2R with R as the resistance of the wires and I as the current that passes through them.
Power at the load is P = VI.
From this one can see that if voltage is increased by say n times, then only $\frac{1}{\text{n}}$ the current is required to deliver the same power. However, if $\frac{1}{\text{n}}$ current is passed
on the same wires, only $\frac{1}{\text{n}^2}$ of the power will be lost.
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A man who cannot see clearly beyond 5 m wants to see stars clearly. He should use a lens of focal length
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(a) – 100 m |
(b) + 5 m |
(c) – 5 m |
(d) Very large |
Two point charges (+Q) and (-2Q) are fixed on the X-axis at positions a and 2a from origin respectively. At what positions on the axis, the resultant electric field is zero
|
(a) Only x = |
(b) Only x = - |
(c) Both x = ± |
(d) x = |
Two wires have resistance of 2W and 4W connected to same voltage, ratio of heat dissipated at resistance is
|
(a) 1 : 2 |
(b) 4 : 3 |
(c) 2 : 1 |
(d) 5 : 2 |
The distance between the extreme points on the periphery of the mirror is called:
One proton beam enters a magnetic field of
T normally, Specific charge =
. velocity =
. What is the radius of the circle described by it
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(a) 0.1 m |
(b) 1 m |
(c) 10 m |
(d) None of these |