The ratio of heat dissipated per second through the resistance $5 \Omega$ and $10 \Omega$ in the circuit given below is: :
JEE MAIN 2024, Diffcult
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$\frac{i_1}{i_2}=\frac{10}{5}=\frac{2}{1}$
$\frac{P_1}{P_2}=\frac{i_1^2 R_1}{i_2^2 R_2}=\left(\frac{2}{1}\right)^2 \times \frac{5}{10}=\frac{2}{1}$
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