MCQ
The reaction, $C{H_3}Br + Na \to {\rm{Product}}$, is called
- APerkin reaction
- BLevit reaction
- ✓Wurtz reaction
- DAldol condensation
$C{H_3}Br + 2Na + BrC{H_3} \to \mathop {{C_2}{H_6}}\limits_{{\rm{ethane}}} + 2NaBr$
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$C{{H}_{3}}OH\xrightarrow{HI}C{{H}_{3}}I\xrightarrow{KCN}$
$C{{H}_{3}}CN\xrightarrow{\text{reduction}}X\xrightarrow{HN{{O}_{3}}}Y$

Reason $(R)$: $\left[\mathrm{Co}(\mathrm{en})_2 \mathrm{Cl}_2\right]^{+}$complex ion has an octahedral geometry.
In the light of the above statements, choose the most appropriate answer from the options given below :