- ✓$[XeF]^+ [SbF_6]^-$
- B$[XeF_3]^-[SbF_4]^-$
- C$Xe^-[PtF_6]^+$
- D$XeF_4$
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$\begin{array}{|l|l|l|l|} \hline & Column\,I & & Column\,II \\ & (Reduction\,process) & & (Charge\,required) \\ \hline (a) & 1\,mol\,of\,MnO_4^-\,to\,Mn^{2+} & (p) & 193000\,\,C \\ \hline (b) & 1\,\,mole\,of\,Cr_2O_7^{2-}\,to\,Cr^{3+} & (q) & 289500\,\,C \\ \hline (c) & 1\,\,mole\,of\,Sn^{4+}\,to\,Sn^{2+} & (r) & 482500\,\,C \\ \hline (d) & 1\,mole\,of\,Al^{3+}\,to\,Al & (s) & 579000\,\,C \\ \hline \end{array}$

(Given atomic number $\mathrm{Sc}: 21, \mathrm{Ti}: 22, \mathrm{~V}: 23, \mathrm{Cr}$ : $24, \mathrm{Mn}: 25, \mathrm{Fe}: 26)$
Precipitate $X$ is
$(A)$ $Fe _4\left[ Fe ( CN )_6\right]_3$
$(B)$ $Fe \left[ Fe ( CN )_6\right]$
$(C)$ $K _2 Fe \left[ Fe ( CN )_6\right]$
$(D)$ $KFe \left[ Fe ( CN )_6\right]$
Among the following, the brown ring is due to the formation of
$(A)$ $\left[ Fe ( NO )_2\left( SO _4\right)_2\right]^{2-}$
$(B)$ $\left[ Fe ( NO )_2\left( H _2 O \right)_4\right]^{3+}$
$(C)$ $\left[ Fe ( NO )_4\left( SO _4\right)_2\right]$
$(D)$ $\left[ Fe ( NO )\left( H _2 O \right)_5\right]^{2+}$