MCQ
The reagent $(s)$ required for the following conversion are


- A$(i) NaBH_4$ , $(ii)$ Raney $Ni/H_2$, $(iii) H_3O^+$
- B$(i) LiAlH_4$ $(ii) H_3O^+$
- C$(i) B_2H_6$ , $(ii) DIBAL-H$ , $(iii) H_3O^+$
- ✓$(i) B_2H_6$ , $(ii) SnCl_2/HCl$, $(iii) H_3O^+$


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phenol $\xrightarrow[{reaction}]{{\operatorname{Re} imer - Tiemann}}X\xrightarrow[{(ii)\,{H^ \oplus }}]{{(i)\,NaOH\,conc}}Z$
Product $Z$ is
$Ln$ (Lanthanide) $\xrightarrow{{Burn{\text{ }}With{\text{ }}{{\text{O}}_2}{\text{ }}}}Y$
$Ln$ (Lanthanide) $\xrightarrow{{Heated{\text{ }}with{\text{ }}{{\text{N}}_2}}}Z$
$X,\, Y$ and $Z$ are respectively:-