The resistance of a wire is ${10^{ - 6}}\,\Omega $ per meter. It is bend in the form of a circle of diameter $2\,m$. A wire of the same material is connected across its diameter. The total resistance across its diameter $AB$ will be
A$\frac{4}{3}\pi \times {10^{ - 6}}\,\Omega $
B$\frac{2}{3}\pi \times {10^{ - 6}}\,\Omega $
C$0.88 \times {10^{ - 6}}\,\Omega $
D$14\pi \times {10^{ - 6}}\,\Omega $
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C$0.88 \times {10^{ - 6}}\,\Omega $
c Resistance across $AB = \frac{1}{{R'}} = \frac{1}{R} + \frac{1}{R} + \frac{1}{{{R_1}}}$ ${R_1} = 2 \times {10^{ - 6}}\,\Omega $
On solving, $R' = 0.88 \times {10^{ - 6}}\,\Omega $
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