- AWavelength of light.
- BDiameter of objective.
- CLength of the tube.
- DFocal length of eyepiece.
Explanation:
The resolving power of a telescope can be given as:
Resolving power $=\frac{1}{\text{d}(\theta)}=\frac{1}{1.22\lambda/ \text{D}}=\frac{\text{D}}{1.22}$ (wavelength)
So, resolving power can be increased by decreasing the wavelength and increasing the diameter of objective.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
16 gm sample of a radioactive element is taken from Bombay to Delhi in 2 hour and it was found that 1 gm of the element remained (undisintegrated). Half life of the element is
|
(a) 2 hour |
(b) 1 hour |
(c) |
(d) |
A conducting square loop of side L and resistance R moves in its plane with a uniform velocity v perpendicular to one of its sides. A magnetic induction B constant in time and space, pointing perpendicular and into the plane of the loop exists everywhere. The current induced in the loop is

|
(a) |
(b) |
(c) |
(d) Zero |
Four plates of the same area of cross-section are joined as shown in the figure. The distance between each plate is d. The equivalent capacity across A and B will be

|
(a) |
(b) |
(c) |
(d) |
The magnetism of magnet is due to
|
(a) The spin motion of electron |
(b) Earth |
|
(c) Pressure of big magnet inside the earth |
(d) Cosmic rays |
In helium nucleus, there are
|
(a) 2 protons and 2 electrons |
(b) 2 neutrons, 2 protons and 2 electrons |
|
(c) 2 protons and 2 neutrons |
(d) 2 positrons and 2 protons |
In radio theraphy, X-rays are used to
| (a) Detect bone fractures |
(b) Treat cancer by controlled exposure |
| (c) Detect heart diseases | (d) Detect fault in radio receiving circuits |
When yellow light is incident on a surface, no electrons are emitted while green light can emit. If red light is incident on the surface, then
|
(a) No electrons are emitted |
|
(b) Photons are emitted |
|
(c) Electrons of higher energy are emitted |
|
(d) Electrons of lower energy are emitted |