MCQ
The shaded region in the given figure is a graph of $.....$
  • A
    $4 x-2 y \leq 3$
  • $4 x-2 y \leq-3$
  • C
    $2 x-4 y \geq 3$
  • D
    $2 x-4 y \leq-3$

Answer

Correct option: B.
$4 x-2 y \leq-3$
b
The given line intersects $\mathrm{X}$ - axis at $\left(-\frac{3}{4}, 0\right)$ and $\mathrm{Y}$ - axis at $\left(0, \frac{3}{2}\right)$

$\therefore$ Equation of the line $\frac{x}{-\frac{3}{4}}+\frac{y}{\frac{3}{2}}=1$

$\therefore-4 x+2 y=3$

$\therefore 4 x-2 y=-3$

Taking $x=y=0 \Rightarrow 0-0 \leq-3$ which is not true.

$\therefore 4 x-2 y \leq-3$ is a half plane not containing $(0,0).$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The volume of the parallelopiped whose edges are represented by $ - 12i + \alpha k,\,\,3j - k$ and $2i + j - 15k$ is $546.$  Then $\alpha = $
Consider the binary operation × on Q defind by a × b = a + 12b + ab for a, b ∈ Q. Find $2\times\frac{1}{3}$
  1. $\frac{20}{3}$
  2. 4
  3. 18
  4. $\frac{16}{3}$
If the equation ${\sin ^{ - 1}}\left( {x - 1} \right) + {\cos ^{ - 1}}\left( {x - 3} \right) + {\tan ^{ - 1}}\left( {\frac{x}{{ - {x^2} + 2}}} \right) = m$ holds, then the value of $'m'$ is
A fair coin is tossed $n$-times such that the probability of getting at least one head is at least $0.9 .$ Then the minimum value of $n$ is $....$
For $x > 0$ , let $f(x)\, = \,\int\limits_1^x {\frac{{\log \,t}}{{1 + t}}} \,dt$ then $f(x)\, + \,f\left( {\frac{1}{x}} \right)$ is equal to 
The vectors $\vec{\text{a}}$ and $\vec{\text{b}}$ satisfy the equation $2\vec{\text{a}}+\vec{\text{b}}=\vec{\text{p}}$ and $\vec{\text{a}}+2\vec{\text{b}}=\vec{\text{q}},$ where $\vec{\text{p}}=\hat{\text{i}}+\hat{\text{j}}$ and $\vec{\text{q}}=\hat{\text{i}}-\hat{\text{j}}.$ If $\theta$ is the angle between $\vec{\text{a}}$ and $\vec{\text{b}},$ then:
  1. $\cos \theta = \frac{4}{5}$
  2. $\sin \theta = \frac{1}{\sqrt{2}}$
  3. $\cos \theta = -\frac{4}{5}$
  4. $\cos \theta = -\frac{3}{5}$
Find the minimum value of $f(x)=2 x^3-24 x+107$ in the interval $[1,3]$.
If $\text{f(x)}=\begin{cases}\frac{\sin(\text{a}+1)}{\text{x}},&\text{x}<0\\\text{c},&\text{x}=0\\\frac{\sqrt{\text{x+bx}^2}-\sqrt{\text{x}}}{\text{bx}\sqrt{\text{x}}},&\text{x}>0&\end{cases}$ is continuouse at x = 0, then:
  1. $\text{a}=-\frac{3}{2},\text{b}=0,\text{c}=\frac{1}{2}$
  2. $\text{a}=-\frac{3}{2},\text{b}=1,\text{c}=-\frac{1}{2}$
  3. $\text{a}=-\frac{3}{2},\text{b}\in\text{R}-\{0\},\text{c}=\frac{1}{2}$
  4. $\text{None of these}.$
The solution of the differential equation $\frac{{dy}}{{dx}} = \left( {x - {y}} \right)^2$ when $y(1) = 1$, is
$\sqrt 2 \smallint \frac{{sinx\;dx}}{{{\rm{sin}}\left( {x - \frac{\pi }{4}} \right)}} = $