MCQ
The shape of $XeO _2 F _2$ molecule is
- Atrigonal bipyramidal
- Bsquare plannar
- Ctetrahedral
- ✓see-saw

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$(I)$ cis $- [Co(NH_3)_2(en)_2]^{3+}$ $(II)$ trans $-[IrCl_2(C_2O_4)_2]^{3-}$
$(III)\, [Rh(en)_3]^{3+}$ $(IV)$ cis $-[Ir(H_2O)_3Cl_3$
| List $-I$ | List $-II$ |
| $A$ $XeF_4$ | $1.$ Pyramidal |
| $B$ $XeF_6$ | $2.$ $T-$ shape |
| $C$ $XeO_3$ | $3.$ Distorted octahedral |
| $D$ $XeOF_2$ | $4.$ Square planar |
$(I)$ $CH_3COO^{\Theta}$ $(II)$ $CH_3O^{\Theta}$
$(III)$ $CH_3CH_2^{\Theta}$ $(IV)$ $CH_3SO_3^{\Theta}$
The correct statement($s$) about $P, Q, R$, and $S$ is(are)
($A$) Both $P$ and $Q$ have asymmetric carbon($s$).
($B$) Both $Q$ and $R$ have asymmetric carbon($s$).
($C$) Both $P$ and $R$ have asymmetric carbon($s$).
($D$) $P$ has asymmetric carbon(s), $S$ does not have any asymmetric carbon.