Question
The solution set of the inequality $3 x+5 y<4$ is

Answer

The strict inequality represents an open half plane and it contains the origin, as $(0,0)$ satisfies it.

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Corner points of the feasible region determined by the system of linear constraints are (0, 3), (1, 1) and (3, 0). Let Z = px + qy, where p, q > 0. Condition on p and q so that the minimum of Z occurs at (3, 0) and (1, 1) is:
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