The total energy of the body executing $S.H.M.$ is $E$. Then the kinetic energy when the displacement is half of the amplitude, is
  • A$\frac{E}{2}$
  • B$\frac{E}{4}$
  • C$\frac{{3E}}{4}$
  • D$\frac{{\sqrt 3 }}{4}E$
Medium
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