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Integrals — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsIntegrals1 Mark
MCQ
The value of $\int_0^{\pi / 6} \sin 3 x d x$ is:
  • A
    $-\frac{\sqrt{3}}{2}$
  • B
    $-\frac{1}{3}$
  • C
    $\frac{\sqrt{3}}{2}$
  • D
    $\frac{1}{3}$
✓

Answer

$\begin{array}{l}\text {Let } I=\int_0^{\pi / 6} \sin 3 x d x \\ =\frac{-1}{3}[\cos 3 x]_0^{\pi / 6}=\frac{-1}{3}\left[\cos \frac{\pi}{2}-\cos 0\right]=\frac{-1}{3}(0-1)=\frac{1}{3}\end{array}$

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