MCQ
The value of $\int\left[\sqrt{x}+\frac{1}{\sqrt{x}}\right]^2 d x$ is
  • A
    $x^2-2 x+\log |x|+C$
  • $\frac{x^2}{2}+2 x+\log |x|+C$
  • C
    $x^2+2 x-\log |x|+C$
  • D
    $x^2-x+\log |x|+C$

Answer

Correct option: B.
$\frac{x^2}{2}+2 x+\log |x|+C$
(B) $\frac{x^2}{2}+2 x+\log |x|+C$
$\begin{aligned} I & =\int\left[\sqrt{x}+\frac{1}{\sqrt{x}}\right]^2 d x \\ & =\int\left(x+\frac{1}{x}+2\right) d x \\ & =\int x d x+\int \frac{1}{x} d x+2 \int d x \\ & =\frac{x^2}{2}+\log |x|+2 x+C\end{aligned}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free