MCQ
The value of $\lambda$ for which the equation $2\left(x^2+y^2\right)-$ $6 x+8 y+\lambda=0$ represents a point circle is
  • A
    $\frac{25}{4}$
  • B
    $\frac{4}{25}$
  • $\frac{25}{2}$
  • D
    $\frac{2}{25}$

Answer

Correct option: C.
$\frac{25}{2}$
(C) $\frac{25}{2}$
Explanation : Given equation of circle is
$2\left(x^2+y^2\right)-6 x+8 y+\lambda=0$
or, $\left(x^2+y^2\right)-3 x+4 y+\frac{\lambda}{2}=0\quad \ldots(i) $
If the radius of the circle is zero, then the circle is called a point circle. Thus, eq. (i) will represents a point circle, if
$
\sqrt{\left(\frac{3}{2}\right)^2+(-2)^2-\frac{\lambda}{2}}=0\left[\because r=\sqrt{g^2+f^2-c}\right]
$
$\begin{array}{ll}\Rightarrow & \frac{\lambda}{2}=\frac{25}{4} \\ \Rightarrow & \lambda=\frac{25}{2}\end{array}$

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