
$U=\frac{1}{2} k x^2$
$x^2=\frac{2 U}{k}$
or $x \propto \frac{1}{k}$ (Since $U$ is constant)
Also $T=2 \pi \sqrt{\frac{m}{k}}$
or $T \propto \frac{1}{\sqrt{k}}$
Therefore $x \propto T$
Hence the oscillation with maximum $x$ will have the maximum time period.
$(A)$ The force is zero $t=\frac{3 T}{4}$
$(B)$ The acceleration is maximum at $t=T$
$(C)$ The speed is maximum at $t =\frac{ T }{4}$
$(D)$ The $P.E.$ is equal to $K.E.$ of the oscillation at $t=\frac{T}{2}$

$(A)$ Restoring force is directly proportional to the displacement.
$(B)$ The acceleration and displacement are opposite in direction.
$(C)$ The velocity is maximum at mean position.
$(D)$ The acceleration is minimum at extreme points.
Choose the correct answer from the options given below :