MCQ
Thermodynamically, the most stable form of carbon is
- ADiamond
- ✓Graphite
- CFullerenes
- DCoal
✓
Answer
Correct option: B.
Graphite
b
Graphite is thermodynamically, the most stable allotrope of carbon. That is why $\Delta _fH^o$ (graphite) is taken as zero.
Graphite is thermodynamically, the most stable allotrope of carbon. That is why $\Delta _fH^o$ (graphite) is taken as zero.
$\Delta _fH^o$ (diamond) $= +1.90\,kJ\,mol^{-1}$
$\Delta _fH^o$ (fullerene) $= +38.1\,kJ\,mol^{-1}$
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