Thomson coefficient of a conductor is $10\,\mu V/K$. The two ends of it are kept at ${50\,^o}C$ and ${60\,^o}C$ respectively. Amount of heat absorbed by the conductor when a charge of $10\,C$ flows through it is
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(d) By using $H = \sigma Q\theta $
$ \Rightarrow $ $H = (10 \times {10^{ - 6}}) \times 10 \times (60 - 50) = {10^{ - 3}}J = 1\,\,mJ$
$ \Rightarrow $ $H = (10 \times {10^{ - 6}}) \times 10 \times (60 - 50) = {10^{ - 3}}J = 1\,\,mJ$
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