A resistor dissipates $192\, {J}$ of energy in $1\, {s}$ when a current of $4\, {A}$ is passed through it. Now, when the current is doubled, the amount of thermal energy dissipated in $5 \,{s}$ in $.....\,J.$
JEE MAIN 2021, Medium
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${E}={i}^{2} {Rt}$
$192=16({R})(1)$
${R}=12\, \Omega$
${E}^{1}=(8)^{2}(12)(5)$
$=3840\, {J}$
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