Question
Three circuits, each consisting of a switch ‘S’ and two capacitors, are initially charged, as shown in the figure. After the switch has been closed, in which circuit will the charge on the left-hand capacitor (i) increase, (ii) decrease and (iii) remain same? Give reasons.

Answer

$V_L = 3?$ $V_R = 3?$ (L: Left, R: Right)
$V_L = 6?$ $V_R = 3?$  
$V_L = 2?$ $V_R= 3?$  
Reasons:
  1. No change – (potential same on both capacitors as $(V_L = V_R).$
  2. Charge on left hand capacitor will decrease $(V_L > V_R).$
  3. Charge on left hand capacitor will increase $(V_R > V_L).$

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