MCQ
Three identical balls are projected with the same speed at angle $30^o, 45^o$ and $60^o$. Their ranges are $R_1 R_2$ and $R_3$ respectively. Then
- A$R_1 = R_2 = R_3$
- ✓$R_1 = R_3 < R_2$
- C$R_1 < R_2 < R_3$
- D$R_1 > R_2 > R_3$
✓
Answer
Correct option: B.
$R_1 = R_3 < R_2$
b
$30^{\circ}+60^{\circ}=90^{\circ}$
$30^{\circ}+60^{\circ}=90^{\circ}$
$\therefore \mathrm{R}_{1}=\mathrm{R}_{3}$
and we get maximum range
for $\theta=45^{\circ}$
so $\mathrm{R}_{2}$ will be maximum hence $\mathrm{R}_{1}=\mathrm{R}_{3}<\mathrm{R}_{2}$
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