Three resistances of one ohm each are connected in parallel. Such connection is again connected with $\frac{2}{3}\,\Omega $ resistor in series. The resultant resistance will be ........... $\Omega$
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(c) Resistance of $1\, ohm$ group $ = \frac{R}{n} = \frac{1}{3}\,\Omega $
This is in series with $\frac{2}{3}\,\Omega $ resistor.
$\therefore $Total resistance $ = \frac{2}{3} + \frac{1}{3} = \frac{3}{3}\,\Omega = 1\,\Omega $
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