Download App

Quadrilaterals — Maths STD 9 — Question

Gujarat BoardEnglish MediumSTD 9MathsQuadrilaterals1 Mark
MCQ
Three Statements are given below:
  1. In a, Parallelogram the angle bisectors of 2 adjacent angles enclose a right angle.
  2. The angle bisector of a Parallelogram form a Rectangle.
  3. The Triangle formed by joining the mid-points of the sides of an isosceles triangle is not necessarily an isosceles triangle.
    Which of the statement/ statements is/ are True?
  • A
    II
  • B
    I
  • C
    I and III
  • D
    I and II
✓

Answer

  1. I and II
    Solution:
  1. The adjacent angles of a parallelogram are supplementary. Their halves add up to 90º. So the angle bisectors enclose a right angle.
  2. All the adjacent angle bisectors enclose right angles. So we have a rectangle being enclosed by the angle bisectors of a parallelogram.
  3. The triangle formed by joining the mid-points of the sides of an isosceles triangle is always an isosceles triangle, because halves of equal sides are also equal.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q" from Quadrilaterals→Quadrilaterals — all question types→Maths STD 9 question papers→Gujarat Board STD 9 question papers→Gujarat Board question paper generator→

Similar questions

The length of the longest rod that can fit in a cubical vessel of side 10cm, is:
  1. $10\text{cm}$
  2. $ 20\text{cm}$
  3. $ 10\sqrt{2}\text{cm}$
  4. $ 10\sqrt{3}\text{cm}$
→
The value of $2 . \overline{45}+0 . \overline{36}$ in the simple form is
→
The base of an isosceles right triangle in 30 cm. Its area is
→
The length of each side of an equilateral triangle having an area of $25\sqrt{3}\text{cm}^2$ is:
→
In $\triangle\text{ABC},$ EF is the line segment joining the mid-points of the sides AB and AC. BC = 7.2cm, Find EF = ?
→
Three cubes of metal with edges 3cm, 4cm and 5cm respectively are melted to form a single cube. The lateral surface area of the new cube formed is:
  1. 72cm2
  2. 144cm2
  3. 128cm2
  4. 256cm2
→
If (x + 5) is a factor of = x3 - 20x + 5k then k = ?
  1. -5
  2. 5
  3. 3
  4. -3
→
In $\triangle\text{ABC, AB = AC}$ and $\angle\text{B}=50^{\circ}.$ Then, $\angle\text{A = } ?$
→
ABCD is a parallelogram and E is the mid-point of BC. DE and AB when produced meet at F. Then, AF =
→
In Fig. x + y =
Image
→