MCQ
To carry out above conversion, $(A)$ and $(B)$ respectively, are
- A$NaNH_2 ,Cl - CH_2 - CH_2 - CH_2 -Br$
- B$NaNH_2 , F-CH_2 -CH_2 -CH_2 -Br$
- ✓$NaNH_2 , I - CH_2 -CH_2 -CH_2 -Br$
- D$NaNH_2 , I-CH_2 -CH_2 -CH_2 -I$
✓
Answer
Correct option: C.
$NaNH_2 , I - CH_2 -CH_2 -CH_2 -Br$
c
$(c)$ Acid-base reaction follower by $S_{N^2}$
$\therefore$ $I$ is better leaving group than $Br$.
$\therefore$ $(c)$ is favourable.
$(c)$ Acid-base reaction follower by $S_{N^2}$
$\therefore$ $I$ is better leaving group than $Br$.
$\therefore$ $(c)$ is favourable.
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