MCQ
- A12.5cm2
- BNone of these.
- C13.5cm2
- D11.5cm2
✓
Answer
- 13.5cm2
Solution:
As D and E are the midpoints of AB and AC.
So, by mid-point theorem
$\text{DE} = \frac{\text{BC}}{2} = \frac{12}{2} = 6\text{cm}$
$\text{AD} = \frac{\text{AB}}{2} = \frac{9}{2} = 4.5\text{cm}$
Area of $\triangle\text{ADE} = 0.5 × \text{DE} × \text{AD}$
$= 0.5 × 6 × 4.5 = 13.5\text{cm}^2$
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