Question
Truth table for the given circuit will be
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Answer
Truth table of the circuit is as follows
| $x$ | $y$ | $\bar x$ | $a= x.y$ | $b=\bar x.y$ | $z=\bar {a.b}$ |
| $0$ | $0$ | $1$ | $0$ | $0$ | $1$ |
| $0$ | $1$ | $1$ | $0$ | $1$ | $1$ |
| $1$ | $0$ | $0$ | $0$ | $0$ | $1$ |
| $1$ | $1$ | $0$ | $1$ | $0$ | $1$ |
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