MCQ
Turnbull's blue is:
- AFe3[Fe(CN)6]2
- BK4Fe(CN)6
- CK3Fe(CN)6
- DNa4Fe(CN)6
✓
Answer
- Fe3[Fe(CN)6]2
Explanation:
Turnbull's blue is Fe3[Fe(CN)6]2.
The structure is as follows:
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Glucose and mannose are
Number of moles of $PhMgBr$ consumed $(x)$ in $(a)$ $+$ molecular mass of $(C)$
→Major product ,$(B)$ in this reaction is
→The element californium belongs to the family
Which of the following is $INCORRECT$ match for the suitable enzyme catalyst of the given reaction
→Given that
→$\Lambda_{ m }^{\alpha}=133.4\,\left( AgNO _{3}\right) ; \Lambda_{ m }^{\alpha}=149.9( KCl )$
$\Lambda_{ m }^{\alpha}=144.9\, S\, cm ^{2} \,mol ^{-1}\left( KNO _{3}\right)$
the molar conductivity at infinite dilution for $AgCl$ is $.......\, S \,cm ^{2}\, mol ^{-1}$
$(NH_4)_2Cr_2O_7$ (Ammonium dichromate) is used in fire works. The green coloured powder blown in air is
→The effective atomic number of cobalt in the complex ${[Co{(N{H_3})_6}]^{3 + }}$ is
→Select the evidence for the open chain structure of glucose
For a first order reaction, rate constant is 0.6932hr−1, then half - life for the reaction is: