MCQ
Two balls are projected upward simultaneously with speeds $40 \,m / s$ and $60 \,m / s$. Relative position $(x)$ of second ball w.r.t. first ball at time $t=5 s$ is .......... $m$ [Neglect air resistance].
- A$20$
- B$80$
- ✓$100$
- D$120$
✓
Answer
Correct option: C.
$100$
c
(c)
(c)
$S_{ rel }=U_{ rel } t+\frac{1}{2} a_{ rel } t^2$
$\Rightarrow S_{ rel }=(60-40) 5 \quad\left(a_{ rel }=0\right)$
$\Rightarrow S_{ rel }=100 \,m$
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