$5 \sqrt{3}=\frac{(10)^2 \sin 2 \theta}{g} \text { or } \sin 2 \theta=\frac{\sqrt{3}}{2}$
$\therefore 2 \theta=60^{\circ} \text { or } \theta=30^{\circ}$
Two different angles of projection are therefore, $\theta$ and $\left(90^{\circ}-\theta\right)$ or $30^{\circ}$ and $60^{\circ}$.
Two different angles of projection are therefore, $\theta$ and $\left(90^{\circ}-\theta\right)$ or $30^{\circ}$ and $60^{\circ}$.
$T_1=\frac{2 u \sin 30^{\circ}}{g}=1\,s$
$T_2=2 \frac{u \sin 60^{\circ}}{g}=\sqrt{3}\,s$
$\Delta t=T_2-T_1=(\sqrt{3}-1)\,s$
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| List - I | List - II |
|---|---|
| $(A)$ Distance between earth and stars | $(1)$ Microns |
| $(B)$ Inter-atomic distance in a solid | $(2)$ Angstroms |
| $(C)$ Size of the nucleus | $(3)$ Light years |
| $(D)$ Wavelength of infrared laser | $(4)$ Fermi |
| $(5)$ Kilometres |
$(A)$ $\mathrm{C}_{\mathrm{p}}-\mathrm{C}_{\mathrm{v}}$ is larger for a diatomic ideal gas than for a monoatomic ideal gas
$(B)$ $\mathrm{C}_{\mathrm{p}}+\mathrm{C}_{\mathrm{v}}$ is larger for a diatomic ideal gas than for a monoatomic ideal gas
$(C)$ $\mathrm{C}_{\mathrm{p}} / \mathrm{C}_{\mathrm{v}}$ is larger for a diatomic ideal gas than for a monoatomic ideal gas
$(D)$ $\mathrm{C}_{\mathrm{p}} \cdot \mathrm{C}_v$ is larger for a diatomic ideal gas than for a monoatomic ideal gas
