MCQ
Two coherent plane light waves of equal amplitude makes a small angle $\alpha ( < < 1)$ with each other . They fall almost normally on a screen. If $\lambda $ is the wavelength of light waves, the fringe width $\Delta x$ of interference patterns of the two sets of waves on the screen is
  • A
    $\frac{{2\lambda }}{\alpha }$
  • B
    $\frac{{\lambda }}{\alpha }$
  • $\frac{{\lambda }}{(2\alpha )}$
  • D
    $\frac{{\lambda }}{\sqrt \alpha }$

Answer

Correct option: C.
$\frac{{\lambda }}{(2\alpha )}$
c
$\Delta x = \frac{\lambda }{{(2\alpha )}}$

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