Two coils have a mutual inductance 0.005 H. The current changes i… - Vidyadip

Question

Two coils have a mutual inductance $0.005 H$. The current changes in the first coil according to equation $I = I _0 \sin$
$\Omega t$, where $I _0=10 A$ and $\omega=100 \pi rad s ^{-1}$. The maximum value of emf in the second coil is

✓

Answer

$(c)\ 5 \pi$
Explanation :
$\varepsilon=M \frac{d I}{d t}$
$=M \frac{d}{d t}\left[I_0 \sin \omega t\right]=M I_0 \omega \cos \omega t $
$ E _{\max }=M I_0 \omega[\text { Max. value of } \cos \omega t=1] $
$ =0.005 \times 10 \times 100 \pi=5 \pi V$

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