Question
Two opposite charged particles oscillate about their mean equilibrium position in free space, with a frequency of $10^9 \ Hz.$ The wavelength of the corresponding electromagnetic wave produced is $.........:$
✓
Answer
Electromagnetic wave $V = 3\times 10^8m/s$
Given frequency $(f) = 10^9Hz$
$\text{V}=\text{f}\lambda$
$\lambda=\frac{\text{V}}{\text{f}}$
$=\frac{3 \times 10^8} {10^9}$
$= 0.3m$
Given frequency $(f) = 10^9Hz$
$\text{V}=\text{f}\lambda$
$\lambda=\frac{\text{V}}{\text{f}}$
$=\frac{3 \times 10^8} {10^9}$
$= 0.3m$
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