Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. The amplitude and time period for both particles are same and equal to $A$ and $T,$ respectively. At time $t=0$ one particle has displacement $A$ while the other one has displacement $\frac {-A}{2}$ and they are moving towards each other. If they cross each other at time $t,$ then $t$ is
A$\frac{{5T}}{6}$
B$\frac{{T}}{3}$
C$\frac{{T}}{4}$
D$\frac{{T}}{6}$
JEE MAIN 2016, Diffcult
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D$\frac{{T}}{6}$
d Angle covered to meet $\theta=60^{\circ}=\frac{\pi}{3} \mathrm{rad}$
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