
- Describe the motion of two bobs.
- Draw a graph showing variation in energy of either pendulum with time, for
where T is the period of each pendulum.

PEA = 0, PEB = E, KEA = KEB = 0
K.E. of both are zero. Now bob is released.
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reaches to A and collide elastically as both bobs are identical then,
KEA = 0, KEB = E, PEA = 0
PEB = 0
AT reaches at it’s maximum height and B remains at it’s lowest position.
KEA = 0, KEB = E, PEA = E, PEB = 0

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Bob A hits the bob B which was at rest elastically and ball A becomes at rest, B moves upward.
KEA = 0, KEB = E, PEA = E, PEB = 0
EA = 0, EB = E
At Bob B is at its maximum height and A is at lower height.
So, KEA = 0, KEB = 0, PEA = 0, PEB = E
| Time t | KEA | PEA | EA | KEB | PEB | EB |
| 0 | 0 | 0 | 0 | 0 | E | E |
![]() | 0 | 0 | E | 0 | 0 | 0 |
![]() | 0 | 0 | 0 | 0 | E | E |
| E | 0 | E | 0 | 0 | 0 | |
![]() | 0 | 0 | 0 | 0 | E | E |

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| Temperature | Pressure thermometer A | Pressure thermometer B |
| Triple-point of water | 1.250 × 105Pa | 0.200 × 105Pa |
| Normal melting point of sulphur | 1.797 × 105Pa | 0.287 × 105Pa |
What is the absolute temperature of normal melting point of sulphur as read by thermometers A and B?
What do you think is the reason behind the slight difference in answers of thermometers A and B? (The thermometers are not faulty). What further procedure is needed in the experiment to reduce the discrepancy between the two readings?

