MCQ
Two projectiles are projected at $30^{\circ}$ and $60^{\circ}$ with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:
- A$2: \sqrt{3}$
- B$\sqrt{3}: 1$
- ✓$1: 3$
- D$1: \sqrt{3}$
✓
Answer
Correct option: C.
$1: 3$
c
$H _{\max }=\frac{ u ^2 \sin ^2 \theta}{2 g }$
$H _{\max }=\frac{ u ^2 \sin ^2 \theta}{2 g }$
$\frac{ H _1}{ H _2}=\frac{\sin ^2 \theta_1}{\sin ^2 \theta_2}=\frac{1}{3}$
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