Two resistors $400\, \Omega$ and $800\, \Omega$ are connected in series across a $6 V$ battery. The potential difference measured by a voltmeter of $10\, k \Omega$ across $400\, \Omega$ resistor is close to$....V$
JEE MAIN 2020, Medium
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So the potential difference in voltmeter across
the points $A$ and $B$ is $\frac{6}{1185} \times 385=1.949 V$
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