MCQ
Two simple pendulums whose lengths are $100 \ cm$ and $121 \ cm$ are suspended side by side. Their bobs are pulled together and then released. After how many minimum oscillations of the longer pendulum, will the two be in phase again
  • A
    $11$
  • $10$
  • C
    $21$
  • D
    $20$

Answer

Correct option: B.
$10$
Let $T_1$ and $T_2$ are the time period of the two pendulums $T_1=2 \pi \sqrt{\frac{100}{g}} \text { and } T_2=2 \pi \sqrt{\frac{121}{g}}\ (T_1)=  10$

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