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Model Paper 10 — NEET STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceNEETModel Paper 104 Marks
MCQ
Two solid bars are having Young's modulus $Y _1$ and $Y _2$ in the ratio $\left( Y _1 / Y _2\right)=4$. If th bars are made up of the material with the same density, then the ratio of the speed of longitudinal waves in the solid bars, i.e. $\left( v _1 / v _2\right)$ is:
  • A
    3
  • B
    1
  • C
    2
  • D
    4
✓

Answer

C. 2
Explanation:
$v=\sqrt{\frac{Y}{\rho}}$
where $Y =$ Young's modulus
$\rho=$ Mass density
Since solid bars are made up of the materials with same density,
hence $\rho_1=\rho_2$ and $\frac{v_1}{v_2}=\sqrt{\frac{Y_1}{Y_2}}=\sqrt{4}=2$

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