- A$3h_1$
- B$2h_1$
- C$h_1/2$
- ✓$h_1/3$
$=\frac{\sin ^{2} \theta_{2}}{\sin ^{2} \theta_{1}}=\frac{\sin ^{2} \pi / 6}{\sin ^{2} \pi / 3}=\frac{1}{3}$
$\therefore \quad \mathrm{h}_{2}=\mathrm{h}_{1} / 3$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$A.$ The force acting on a planet is inversely proportional to square of distance from sun.
$B.$ Force acting on planet is inversely proportional to product of the masses of the planet and the sun
$C.$ The centripetal force acting on the planet is directed away from the sun.
$D.$ The square of time period of revolution of planet around sun is directly proportional to cube of semi-major axis of elliptical orbit.
Choose the correct answer from the options given below :

(Use $g=\frac{G M}{R^{2}}=9.8 \,ms ^{-2}$ and radius of earth, $R =6400\, km .]$
(Take speed of sound in air as $340\, {ms}^{-1}$ )
