Two waves executing simple harmonic motion travelling in the same direction with same amplitude and frequency are superimposed. The resultant amplitude is equal to the $\sqrt{3}$ times of amplitude of individual motions. The phase difference between the two motions is $.....(degree)$
JEE MAIN 2022, Medium
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$A _{\text {resultrant }}=\sqrt{ A _{1}^{2}+ A _{2}^{2}+2 A _{1} A _{2} \cos \phi}$
$\sqrt{3} A =\sqrt{ A ^{2}+ A ^{2}+2 A ^{2} \cos \phi}$
$3 A ^{2}=2 A ^{2}+2 A ^{2} \cos \phi$
$\cos \phi=\frac{1}{2}$
$\therefore \phi=60^{\circ}$
$\therefore \text { Phase difference }=60 \text { degree }$
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