MCQ
Under the same condition, how many $ml$ of $1M\, KOH$ and $0.5\,M\, H_2SO_4$ solution, respectively, when mixed to from a total volume of $100\, ml$, produce maximum rise in temperature ?
- A$67, 33$
- B$33,67$
- C$40, 60$
- ✓$50, 50$
✓
Answer
Correct option: D.
$50, 50$
d
Rise in temperature will be highest if the ectent of neutralixation reaction is higher due to which the heat evolved will be greater in quantity.
Rise in temperature will be highest if the ectent of neutralixation reaction is higher due to which the heat evolved will be greater in quantity.
$g$ equation = equivalent = Volume $\times$ normality
normality = molarity $\times n-$ factor
For newtralisation reaction,
$g$ equation of acid $=g$ equation of base
$v \times 0.5 \times 2=(100-v) \times 1 \times 1$
$\Rightarrow v=100-v$
$\Rightarrow 2 v=100$
$\Rightarrow v=50 ml$
$\therefore$ Volume of $H_2SO_4=v 50 ml$
and, Volume of $K O H=100-v=100-50=50 ml$
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