Under what condition current passing through the resistance $R$ can be increased by short circuiting the battery of emf $E_2$. The internal resistances of the two batteries are $r_1$ and $r_2$ respectively.
Medium
Download our app for free and get started
$\frac{E_{1}}{r_{1}+R}>\frac{E_{2}+E_{1}}{r_{1}+r_{2}+R}$
$E_{1} r_{1}+E_{1} r_{2}+E_{1} R>E_{2} r_{1}+E_{2} R+E_{1} r_{1}+E_{1} R$
$E_{1} r_2 >E_{2}\left(r_{1}+R\right)$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionA wire of non-uniform cross-section is carrying a steady current. Along the wire
- 2The reading of an ideal voltmer in the circuit shown is.....$V$View Solution
- 3View SolutionResistance of one carbon filament and one tungsten lamp are measured individually when the lamp are lit and compared with their respective resistances when cold. Which one of the following statements will be true
- 4A current $I$ is passing through a wire having two sections $P$ and $Q$ of uniform diameters $d$ and $d/2$ respectively. If the mean drift velocity of electrons in sections $P$ and $Q$ is denoted by $v_P$ and $v_Q$ respectively, thenView Solution
- 5View SolutionThe magnitude and direction of the current in the circuit shown will be
- 6A $1\,m$ long copper wire carries a current of $1\,A$. If the cross section of the wire is $2.0\,mm ^{2}$ and the resistivity of copper is $1.7 \times 10^{-8}\,\Omega\,m$. the force experienced by moving electron in the wire is $\times 10^{-23}\,N$. (charge on electron $=1.6 \times 10^{-19}\,C$ )View Solution
- 7Four equal resistance dissipated $5 \,W$ of power together when connected in series to a battery of negligible internal resistance. The total power dissipated in these resistance when connected in parallel across the same battery would be ........... $W$View Solution
- 8In the following circuit, the current through the resistor $R(=2 \Omega)$ is $I$ Amperes. The value of $I$ isView Solution
- 9Two resistances are joined in parallel whose resultant is $\frac{6}{8}\,ohm$. One of the resistance wire is broken and the effective resistance becomes $2\,\Omega $. Then the resistance in ohm of the wire that got broken wasView Solution
- 10View SolutionTwo wires of the same material are given. The first wire is twice as long as the second and has twice the diameter of the second. The resistance of the first will be