Question
Using truth table prove that : $p \leftrightarrow q=(p \wedge q) \vee(\sim p \wedge \sim q)$

Answer

1

2

3

 4

5

6

   7

   8

   A

   B

P

q

$p \leftrightarrow q$

$p \wedge q$

$\sim p$

$\sim q$

$\begin{gathered}\sim p \wedge \\ \sim q\end{gathered}$

$A \vee B$

T

T

F

F

 

T

F

T

F

T

F

F

T

T

F

F

F

F

F

T

T

 

F

T

F

T

F

F

F

T

T

F

F

T

By column number 3 and 8
p ↔ q ≡ (p ∧ q) ∨ (~p ∧ ~q)

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